Chemistry - ALCOHOL & ETHER Question with Solution | TestHub
Total number of stereoisomers of product (B) will be:
Answer:
Solution:
Question Explanation:
The question asks for the total number of stereoisomers of the final product B.
Concept:
This question is based on oxidative cleavage by HIO4 , reduction of carbonyl compounds by LiAlH4 and counting of stereoisomers of product B.
Solution:
Step 1: Oxidative Cleavage by HIO4
Step 2: Reduction by LiAlH4
Step 3: Counting of stereoisomers of compound B (Octane-2,7-diol).
Compound (B) contains two chiral centres and also has a plane of symmetry. Therefore, it exhibits a
meso form. Hence, the total number of stereoisomers of compound (B) is 3 — out of which 2 are
optically active enantiomers and 1 is optically inactive (meso form).