Lucas test is used to make distinction between $1^{\circ}, 2^{\circ}$ and $3^{\circ}$ alcohols
$R O H + H C l \overset{A n h y d r o u s Z n C l_{2}}{\to} R C l + H_{2} O$
$C o n c . W h i t e t u r b i d i t y$
This shows that :

Question

Lucas test is used to make distinction between 1 ∘ , 2 ∘ and 3 ∘ alcohols R O H + H C l &#x2192; A n h y d r o u s &#xA0; Z n C l 2 R C l + H 2 O &#xA0; &#xA0; &#xA0; &#xA0; &#xA0; &#xA0; &#xA0; &#xA0; &#xA0; &#xA0; &#xA0; C o n c . &#xA0; &#xA0; &#xA0; &#xA0; &#xA0; &#xA0; &#xA0; &#xA0; &#xA0; &#xA0; &#xA0; &#xA0; &#xA0; &#xA0; &#xA0; &#xA0; &#xA0; &#xA0; &#xA0; &#xA0; &#xA0; &#xA0; &#xA0; &#xA0; &#xA0; &#xA0; &#xA0; &#xA0; W h i t e &#xA0; t u r b i d i t y This shows that :

TestHub · Accepted Answer

Explain question:

Question is asking wrest statement for given $R \times n$ .

Concept:

In Lucas test Alcohol is treated with HCl acid in presence of anhydrous $ZnCl_{2}$ . Alcohol are soluble in aqueous HCl but chlorides gives turbidity. Since reaction follows $SN_{1}$ hence $3^{\circ}$ Alcohol gives turbidity immediately followed by $2^{\circ}$ alcohol and $1^{\circ}$ alcohol does not gives lucas test.

Solution:

A) Proton acceptor is base hence A is correct

C) connecter is acidic strength, faster is reaction with Na hence C is incorrect

D) During victor meyer $1^{\circ}$ alcohol → Red, $2^{\circ}$ alcohol → Blue, $3^{\circ}$ alcohol → white or no reaction.

D is correct

Asnwer : A, B, D

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