Zoology - Principles of Inheritance and Variation Question with Solution | TestHub

ZoologyPrinciples of Inheritance and VariationMiscellaneous/MixedEasy2 minPYQ_2020
ZoologyEasysingle choice

An individual homozygous for genes cd is crossed with wild type and F1crossed back with the double recessive. The appearance of the offspring is as follows
+ + →        903
cd →         897
+d →         98
c+ →         102

The distance between the genes c and d is

Options:

Answer:
D
Solution:

% of recombination = Distance between two genes =Total no. of recombinant phenotypesTotal no. of progeny x 100                                                                                                                                                                                                = 200 x 1002000 = 10 % or 10 cM

Stream:NTA_ABHYAS_NEETSubject:ZoologyTopic:Principles of Inheritance and VariationSubtopic:Miscellaneous/Mixed
⏱ 2mℹ️ Source: PYQ_2020

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