A total of 512 seeds are collected from the cross between AaBb × AaBb. Find the number of plants produced with the genotype AAbb and Aabb.

Zoology - Principles of Inheritance and Variation Question with Solution | TestHub

ZoologyPrinciples of Inheritance and VariationMonohybrid and Dihybrid CrossesEasy2 minPYQ_2020

ZoologyEasysingle choice

A total of 512 seeds are collected from the cross between AaBb $\times$ AaBb. Find the number of plants produced with the genotype AAbb and Aabb.

Options:

Answer:

Solution:

For a dihybrid cross, the genotypic ratio will be represented as AABB:AaBB:AABb:AaBb:AAbb:Aabb:aaBB:aaBb:aabb :: 1:2:2:4:1:2:1:2:1.

Therefore, the ratio of plants with genotype AAbb and Aabb will be $\frac{3}{16}$

Hence, the number of plants with genotype AAbb and Aabb will be $\frac{3}{16} x 512 = 96$

Stream:NTA_ABHYAS_NEETSubject:ZoologyTopic:Principles of Inheritance and VariationSubtopic:Monohybrid and Dihybrid Crosses

⏱ 2mℹ️ Source: PYQ_2020

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