Zoology - Principles of Inheritance and Variation Question with Solution | TestHub
A woman whose mother is colourblind and father is haemophilic marries a man whose mother is haemophilic and father is colourblind. Which of the following is correct about its progeny?
Options:
Answer:
Solution:
Xh= X chromosome carrying colourblindness gene. Xhchromosome carrying the haemophilia gene.
Mother of the woman is colourblind, hence her genotype will be XcXc. Father of the woman is haemophilic, hence his genotype will be XhY. The woman receives one X chromosome from her father (it has to be Xh) and the other X chromosome from her mother (it has to be Xc). Thus the genotype of the woman is Xc Xh(She is a carrier for colourblindness as well as haemophilia)
Mother of the man is haemophilic, hence her genotype will be XhXh. Father of the man is colourblind, hence his genotype will be XcY. The man receives Y chromosome from his father and X chromosome from his mother (it has to be Xh). Thus the genotype of the man is XhY.
The genotypes of their children can be represented as follows
| Xc | Xh | |
| Xh | XcXh daughter: carrier for both diseases | XhXh daughter: haemophilic |
| Y | XcY son: colourblind | XhY son: haemophilic |
