A woman (whose father is colour blind but mother is normal) marries a haemophiliac man with hypertrichosis. What percentage of progeny will show genotypically any two of the traits out of the three me

Question

A woman (whose father is colour blind but mother is normal) marries a haemophiliac man with hypertrichosis. What percentage of progeny will show genotypically any two of the traits out of the three mentioned above at a given time?

TestHub · Accepted Answer

Let Xc be the X chromosome with colourblindness gene, Xh be the X chromosome with haemophilia gene and Yt be the Y chromosome with hypertrichosis gene.

The woman receives on X chromosome from colourblind father and one X chromosome from a normal mother. Her genotype will be XXc. The man is heamophilic with hypertrichosis, so his genotype will be XhYt.

Their possible progenies will be

	Xh	Yt
X	XXh	XYt
Xc	XcXh	XcYt

Genotypically any two of the traits out of the three traits will be seen in XcXh and XcYt. Thus the answer is 50%

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