Individuals homozygous for 'xy' genes were crossed with wild type ' + + '. The F 1 dihybrid thus produced was test crossed. It produced progeny in the following ratio ‘ + + ’ 900 ;

Question

Individuals homozygous for 'xy' genes were crossed with wild type ' + + '. The F 1 dihybrid thus produced was test crossed. It produced progeny in the following ratio ‘ + + ’ 900 ; ‘ + y ’ 115 ; ‘ x y ’ 880 ; ‘ x + ’ 105 . Find out the recombination frequency.

TestHub · Accepted Answer

The following steps can be used to calculate the recombination frequency is-

$R F = (\frac{N R}{T P}) \times 100$ map units where RF is recombinant frequency, NR- number of recombinants, TP- total number of progeny. The total number of recombinants, in this case, is $115 + 105 = 220$ and the total number of progeny is $900 + 115 + 880 + 105 = 2000$ . So the recombination frequency is $\frac{220}{2000} \times 100 = 11$ map units.

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