Zoology - Principles of Inheritance and Variation Question with Solution | TestHub
ZoologyPrinciples of Inheritance and VariationGenetic DisordersMedium2 minPYQ_2011
ZoologyMediumsingle choice
A woman with two genes (one on each X -chromosome) for haemophilia and one gene for colour blindness on the X-chromosome marries a normal man. How will the progeny be?
Options:
Answer:
C
Solution:
Haemophilia and colour blindness both are recessive X-linked traits. They express in males when present in single copy (heterozygous) but in females, they express only when present in homozygous condition.
Results
(a) sons are colourblind and haemophilic.
(b) sons are haemophilic only.
(c) daughters are carrier for colour blindness and haemophilia.
(d) daughters are carrier for haemophilia only.
Stream:JIPMERSubject:ZoologyTopic:Principles of Inheritance and VariationSubtopic:Genetic Disorders
⏱ 2mℹ️ Source: PYQ_2011
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