Zoology - Principles of Inheritance and Variation Question with Solution | TestHub

1 map unit or centimorgan is equivalent to $1\%$ recombination between two genes. The frequency of recombination can be used to depict the arrangement of the genes. Recombination frequency between three genes is $\begin{array}{rl}& A-B=9\%\\ & A-C=17\%\text{ and }\\ & B-C=26\%\end{array}$ By manipulating the three possibilities of their arrangements $\mathrm{A}-\mathrm{B}-\mathrm{C},\mathrm{A}-\mathrm{C}-\mathrm{B}$ and $\mathrm{B}-\mathrm{A}-\mathrm{C}$, it was found that the three gene must be arranged in the order $B-A-C$ with distance between $B-A$ being $9\mathrm{cM}$ and $\mathrm{A}-\mathrm{C}$ being $17\mathrm{cM}$ and the distance between $\mathrm{B}-\mathrm{C}$ being $26\mathrm{cM}$.