A woman with normal vision, but whose father was colour blind, marries a colour blind man. Suppose that the fourth child of this couple was a boy. This boy:NEET 2005

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The woman has normal vision but her father was colour blind so she should be the carrier to the disease as Colour blindness is an X-Linked recessive disorder. The genotype of the woman would be: $22 AA + XX^{C}$ The genotype of man to be colour blind should be: $22 AA + X^{C} Y$

The probability of Male child to be colour blind will $50%$ and the ratio of diseased to a normal male child is $1 : 1$ .

Zoology - Principles of Inheritance and Variation Question with Solution | TestHub

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