Zoology - Organisms and Populations Question with Solution | TestHub

In a stable population, for a gene with two alleles, ' $A$ ' (dominant) and 'a' (recessive), if the frequency of ' $A$ ' is $p$ and the frequency of ' $\mathrm{a}$ ' is $q$, then the frequencies of the three possible genotypes (AA, Aa and aa) can be expressed by the Hardy-Weinberg equation: $p^2+2pq+q^2=1$ where $p^2=$ Frequency of AA (homozygous dominant) individuals $q^2=$ Frequency of aa (homozygous recessive) individuals $2pq=$ Frequency of Aa (heterozygous) individuals. So, $p=0.6$ and $q=0.4$ (given) $\begin{array}{rl}\therefore 2pq(\text{ frequency of heterozygote })& =2\times 0.6\times 0.4\\ & =\mathrm{0.48.}\end{array}$