Zoology - Molecular Basis of Inheritance Question with Solution | TestHub

1 map unit or centimorgan is equivalent to $1\%$ recombination between two genes. The frequency of recombination can be used to depict the arrangement of the genes. Recombination frequency between three genes is $\mathrm{A}-\mathrm{B}=9\%,\mathrm{A}-\mathrm{C}=17\%$ and $B-C=26\%$ By manipulating the three possibilities of their arrangements it can be concluded that the three genes must be arranged in the order $B$ - A - C with distance between B - A being $9\mathrm{cm},\mathrm{A}-\mathrm{C}$ being $17\mathrm{cm}$ and $\mathrm{B}-\mathrm{C}$ being $26\mathrm{cm}$.