At a particular locus, the frequency of 'A' allele is 0.6 and that of 'a' is 0.4. What would be the frequency of heterozygotes in a randomly mating population of equilibrium?

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TestHub · Accepted Answer

According to the Hardy-Weinberg equation,

$P^{2} + 2 P Q + Q^{2} = 1$

Where, $P =$ Dominant allele frequency

$Q =$ Recessive allele frequency

$P^{2} =$ Homozygous dominant genotype

$2 P Q =$ Heterozygous genotype

$Q^{2} =$ Homozygous recessive genotype

Here, P = 0.6 and Q = 0.4

Therefore, $2 P Q = 2 \times 0.6 \times 0.4$

$= 0.48 .$

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