Cystic fibrosis is an autosomal recessive disease. In an island having a population of 200 people, 98 people suffer from cystic fibrosis. How many people are carriers of this disease?

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Cystic fibrosis is caused due to a recessive gene. Individuals suffering from this disease are homozygous recessive. Applying Hardy Weinberg's equation here, $q^{2} = \frac{98}{200} = 0.49$ . Hence, $q = 0.7$ . Thus $p = 1 - q = 0.3 .$

If the carrier of this disease is heterozygous individuals. Their proportion will be $2 p q = 2 \times 0.7 \times 0.3 = 0.42$ . In this population, carriers will be $0.42 \times 200 = 84.$

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