At a particular locus, the frequency of 'A' allele is 0.6 and that of 'a' is 0.4. What would be the frequency of heterozygotes in a random mating population at equilibrium?

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TestHub · Accepted Answer

The mathematical expression to calculate allele frequency can be given as p + q = 1. Where p represents the frequency of dominant allele and q represents the frequency of recessive allele. The bionomial expression of Hardy Weinberg's law to calculate genotype frequency is p²+ 2pq + q²= 1

where p²= homozygoys dominant
2pq = heterozygous dominant
q²= homozygous recessive.
Frequency of heterozygous individuals
= 2 × 0.6 × 0.4 = 0.48.

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