A population is in Hardy-Weinberg equilibrium for a gene with only two alleles. If the gene frequency of an allele'A' is 0.7, genotype frequency of 'Aa' is

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For a gene that exists in two alleles, the Hardy-Weinberg equation states that $(p^{2}) + (2 p q) + {(q)}^{2} = 1$

$f (A A) = p^{2}$ (genotype frequency of homozygotes)

$f (A a) = 2 p q$ (genotype frequency of heterozygotes)

$f (a a) = q^{2}$ (genotype frequency of homozygotes)

If $p = 0.7$ and $q = 0.3,$ then

$f (A A) = p^{2} = {(0.7)}^{2} = 0.49$

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