Zoology - Evolution Question with Solution | TestHub

According to Hardy-Weinberg principle :
Frequency of dominant allele (A) = p

Frequency of recessive allele (a) = q = 0.2

Sum total of all the allelic frequencies is 1, i.e. p+ q = 1 
⇒  p + 0.2 = 1  ⇒  p = 0.8      

Frequency of homozygous dominant individuals = p × p = p² 

Frequency of homozygous recessive individuals = q × q = q²

Frequency of hetrozygous dominant individuals = 2pq = 2 × 0.8 × 0.2 = 0.32

Total Population = 500
Number of heterozygotes in population = 0.32 x 500 = 160