According to Hardy-Weinberg’s principle, if allele one is denoted as ‘A’ and allele two as ‘a’ and their frequencies are denoted by p and q , and if random mating occurs. The frequency of heterozygous

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According to Hardy-Weinberg’s principle, if allele one is denoted as ‘A’ and allele two as ‘a’ and their frequencies are denoted by p and q , and if random mating occurs. The frequency of heterozygous individual would be:

TestHub · Accepted Answer

Hardy-Weinberg’s principle states that the allele frequency of a population remains constant from generation to generation unless specific disturbing influences are introduced. This is called genotype equilibrium.

A single locus with two alleles: allele one is denoted as ‘A’ and allele two as ‘a’ and their frequencies are denoted by p and q;

$\begin{array}{l} frequency (A) = p \end{array}$
frequency $\begin{array}{l} (a) = q \end{array}$

And, $p + q = 1$ .

If mating is random, then new individuals will have:

frequency $(AA) = p^{2}$ for the AA homozygotes in the population,

frequency $(aa) = q^{2}$ for the aa homozygotes, and

frequency $(Aa) = 2 p q$ for the Aa heterozygotes.

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