Zoology - Evolution Question with Solution | TestHub
ZoologyEvolutionModern Theory of EvolutionEasy2 minPYQ_2014
ZoologyEasysingle choice
In a population of 1000 individuals 360 belong to genotype AA, 480 to Aa, and the remaining 160 to aa, Based on this data, the frequency of allele A in the population is:NEET 2014
Options:
Answer:
C
Solution:
According to HardyWeinberg principle:
Frequency of dominant allele (A) = p
Frequency of recessive allele (a) = q
Frequency of AA individuals = p × p = p2
Frequency of aa individuals = q × q = q2
Frequency of Aa individuals = 2pq
Total population = 1000
Frequency of AA individuals = p × p = p2 = 360/1000 = 0.36
Frequency of dominant allele (A) = p = 0.6
Stream:NEETSubject:ZoologyTopic:EvolutionSubtopic:Modern Theory of Evolution
⏱ 2mℹ️ Source: PYQ_2014
Doubts & Discussion
Loading discussions...
