Zoology - Evolution Question with Solution | TestHub

ZoologyEvolutionModern Theory of EvolutionEasy2 minPYQ_2014
ZoologyEasysingle choice

In a population of 1000 individuals 360 belong to genotype AA, 480 to Aa, and the remaining 160 to aa, Based on this data, the frequency of allele A in the population is:NEET 2014

Options:

Answer:
C
Solution:

According to Hardy–Weinberg principle: 
Frequency of dominant allele (A) = p                      
Frequency of recessive allele (a) = q 
Frequency of AA individuals = p × p = p2                  
Frequency of aa individuals = q × q = q2
Frequency of Aa individuals = 2pq                         
Total population = 1000
Frequency of AA individuals = p × p = p2 = 360/1000 = 0.36                  
Frequency of dominant allele (A) = p = 0.6  

Stream:NEETSubject:ZoologyTopic:EvolutionSubtopic:Modern Theory of Evolution
⏱ 2mℹ️ Source: PYQ_2014

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