The potential energy U (in joules) of a particle of mass 2 kg moving along OX is given by U = 4 π 2 ( x − 5 ) 2 ( x is measured in metres from O ). Then :-

Start Free Mock LoginAlready registered? Login here

Physics - W.E.P. Question with Solution | TestHub

PhysicsW.E.P.Conservative force & potential energyMedium3 minQB

PhysicsMediummultiple choice

The potential energy U (in joules) of a particle of mass 2 kg moving along OX is given by $U = \frac{π ^{2}}{4} (x - 5)^{2}$ ( x is measured in metres from O ). Then :-

Options:(select one or more)

Answer:

B, C, D

Solution:

$F = - \frac{d U}{d x} = - \frac{π ^{2}}{2} (x - 5)$ , so $a = - \frac{π ^{2}}{4} (x - 5)$ (m = 2 kg).

a > 0 only when x < 5 (B), a < 0 only when x > 5 (C). Equilibrium at x = 5 is stable, so KE is maximum there (D). Permanent rest is possible only at x = 5 - (A) wrong.

Stream:JEESubject:PhysicsTopic:W.E.P.Subtopic:Conservative force & potential energy

⏱ 3mℹ️ Source: QB

Doubts & Discussion

Loading discussions...