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Physics - W.E.P. Question with Solution | TestHub

PhysicsW.E.P.Conservative force & potential energyMedium3 minQB

PhysicsMediuminteger

The potential energy function for a two dimensional force is $U = + 2 x^{3} - 4 x^{2} y + 6 y^{2}$ where $U$ is in joules. x and y are in meters. The force (in N) acting on particle at $(3, 2)$ is A $\hat{i} + B \hat{j}$ . Find $(A + B)$ .

Answer:

Solution:

$F_{x} = - \frac{\partial U}{\partial x} = - 6 x^{2} + 8 x y, F_{y} = - \frac{\partial U}{\partial y} = 4 x^{2} - 12 y$ .

At (3, 2): $A = - 54 + 48 = - 6, B = 36 - 24 = 12$ , so $A + B = 6$ .

Stream:JEESubject:PhysicsTopic:W.E.P.Subtopic:Conservative force & potential energy

⏱ 3mℹ️ Source: QB

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