A uniform rod having length L , is made of material having density ρ , coefficient of thermal expansion α , and Young's modulus Y. If it placed between two vertical walls having separation L and

Question

A uniform rod having length L , is made of material having density $ρ$ , coefficient of thermal expansion $α$ , and Young's modulus Y. If it placed between two vertical walls having separation L and coefficient of friction for one wall is $2 μ$ and other wall is $μ$ , what is the minimum rise in temperature so that the rod is in equilibrium.

Options:

Answer:

C

Solution:

Maximum upward friction is (2μ+μ)N, with N=YαΔT times area.

Balancing rod weight gives ΔT=Lρg/(3μαY), corresponding to the printed C convention.

TestHub · Accepted Answer

Maximum upward friction is (2μ+μ)N, with N=YαΔT times area. Balancing rod weight gives ΔT=Lρg/(3μαY), corresponding to the printed C convention.

Thermal Properties of Matter - Thermal Expansion Question with Solution | TestHub

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