Thermal Properties of Matter - Thermal Expansion Question with Solution | TestHub
Thermal Properties of MatterThermal ExpansionThermal StressMedium3 minCT49
Thermal Properties of MatterMediuminteger
A thin ring of an alloy of inner diameter 20 cm and cross-sectional area , is heated until it easily slides on a rigid cylinder of diameter 20.025 cm. [For the alloy : ] when the ring cools down, what is the tension (in N) in it?
Answer:
50
Solution:
The circumferential strain on cooling onto the cylinder is Δd/d=0.025/20=0.00125.
Stress=Yε=5×10^8 Pa, so tension=stress×1 mm²=500 N.
Stream:JEESubject:Thermal Properties of MatterTopic:Thermal ExpansionSubtopic:Thermal Stress
⏱ 3mℹ️ Source: CT49
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