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PhysicsSHMCalculation of time periodMedium2 minQB
PhysicsMediumsingle choice

A particle of mass m undergoes oscillation about in a potential energy given by where and a are constant. If the amplitude of oscillation is much smaller than a , the time period is given by

Options:

Answer:
C
Solution:

For small oscillations , so , an SHM with .

T=2\pi\sqrt{\frac{m}{k}}=2\pi\sqrt{\frac{ma^2}{V_0}}}

Answer: C

Stream:JEESubject:PhysicsTopic:SHMSubtopic:Calculation of time period
2mℹ️ Source: QB

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