Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoThermodynamicsMedium2 minQB

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moles of a diatomic gas undergoes the process: $P T^{2} / V =$ constant. Then, the molar heat capacity of the gas during the process will be equal to

Answer:

Solution:

$P T^{2} / V =$ const with $T = \frac{P V}{n R} \Rightarrow P^{3} V =$ const , i.e. $P V^{1/3} =$ const.

$C = C_{V} + \frac{R}{1 - 1/3} = \frac{5 R}{2} + \frac{3 R}{2} = 4 R .$

Stream:JEESubject:PhysicsTopic:Heat & ThermoSubtopic:Thermodynamics

⏱ 2mℹ️ Source: QB

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