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Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoKTGMedium2 minQB

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The P-V graph of two different samples having masses $m_{1}$ and $m_{2}$ of a gas for isothermal processes are shown in figure at temperatures $T_{1}$ and $T_{2}$ respectively.

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Answer:

Solution:

$P V = \frac{m}{M} RT$ . Since the masses differ and are unknown, a larger PV product for curve 2 can come from larger m, larger T, or both; so $T_{2}$ may be equal to $T_{1}$ .

Stream:JEESubject:PhysicsTopic:Heat & ThermoSubtopic:KTG

⏱ 2mℹ️ Source: QB

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