A calorimeter of mass 50 g and specific heat 0.2 cal g⁻¹ °C⁻¹ holds 150 cm³ of water. It cools from 60°C to 40°C in 15 minutes. With 150 cm³ of oil of specific gravity 1.6 in the same calorimeter, it

Question

A calorimeter of mass 50 g and specific heat 0.2 cal g⁻¹ °C⁻¹ holds 150 cm³ of water. It cools from 60°C to 40°C in 15 minutes. With 150 cm³ of oil of specific gravity 1.6 in the same calorimeter, it takes 10 minutes for the same fall. Find the specific heat of the oil, in cal g⁻¹ °C⁻¹.

Answer:

0.39

Solution:

Time is proportional to total heat capacity: $\frac{10 + 150}{15} = \frac{10 + 240 c}{10}$ gives $10 + 240 c = 106.7$ , so $c = 0.389$ .

TestHub · Accepted Answer

Time is proportional to total heat capacity: 15 10 + 150 ​ = 10 10 + 240 c ​ gives 10 + 240 c = 106.7 , so c = 0.389 .

Physics - Heat & Thermo Question with Solution | TestHub

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