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Physics - W.E.P. Question with Solution | TestHub

PhysicsW.E.P.Vertical circular motionMedium2 minQB

PhysicsMediumsingle choice

Passage / Comprehension

Block is taken toward left so that spring is compressed. Now the block is released from rest. Block moves on smooth horizontal surface after leaving spring, then on circular path of radius R (k = mg/2R).

If block is able to complete circular motion then acceleration of block at point A is : (take $g = 10 m / s^{2}$ )

Options:

Answer:

Solution:

To complete circular motion velocity of block after leaving spring

$v = 5 gR$

let spring compressed by \%

$\frac{1}{2} k x^{2} = \frac{1}{2} m v^{2} \frac{1}{2} \frac{m g}{2 R} x^{2} = \frac{1}{2} m v^{2} x = \frac{2 R}{g} x = R 10$

At A $v = 3 gR$

$a_{c} = \frac{v ^{2}}{R} = 3 g at = g a = g 10 = 1010 m / s^{2}$

Stream:JEESubject:PhysicsTopic:W.E.P.Subtopic:Vertical circular motion

⏱ 2mℹ️ Source: QB

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