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Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoHeat TransferMedium2 min

PhysicsMediuminteger

Two rods of different materials have their lengths, diameters and conductivities all in the ratio 1 : 3, with the same temperature difference. The shorter rod conducts 2 cal $s^{- 1}$ . Find the rate in cal $s^{- 1}$ in the larger rod.

Answer:

Solution:

The rate $\propto \frac{k d ^{2}}{l}$ . The factor for the larger rod is $\frac{3 \times 9}{3} = 9$ . $2 \times 9 = 18$ cal $s^{- 1}$ .

Subject:PhysicsTopic:Heat & ThermoSubtopic:Heat Transfer

⏱ 2m

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