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PhysicsSHMOscillations and SHMMedium2 min

PhysicsMediumnumerical

The same rod ( $m = 1$ kg) has the spring attached at its midpoint instead, $k = 400$ N/m. Find the angular frequency, in rad/s.

Answer:

17.30

Solution:

Torque = $\frac{k L ^{2}}{4} θ$ , $I = m L^{2} /3$ . $ω^{2} = \frac{3 k}{4 m} = 300$ , $ω = 17.3$ rad/s.

Subject:PhysicsTopic:SHMSubtopic:Oscillations and SHM

⏱ 2m

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