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PhysicsHeat & ThermoThermodynamics Laws & Specific Heats of GasesMedium2 minQB

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Two moles of monoatomic gas and one mole of diatomic gas are mixed. The molar specific heat at constant volume of the mixture is:

Answer:

Solution:

$C_{v} = \frac{2 \times \frac{3}{2} R + 1 \times \frac{5}{2} R}{3} = \frac{5.5}{3} R = \frac{11}{6} R$ . A.

Subject:PhysicsTopic:Heat & ThermoSubtopic:Thermodynamics Laws & Specific Heats of Gases

⏱ 2mℹ️ Source: QB

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