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If block A is moving with an acceleration of $5 m / s^{2}$ , the acceleration of B w.r.t. ground is

Answer:

Solution:

By virtual work method :

$2 Y x_{A} = T \times x_{B A}$

$2 x_{A} = x_{B A}$

$x_{B A} = 2 \times 5 = 10$

$a_{B} = a_{B A} + a_{A}$

$1 0^{2} + 5^{2} = 100 + 25 = 125$

Stream:JEESubject:PhysicsTopic:NLM

⏱ 2mℹ️ Source: QB

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