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Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoThermodynamics Laws & Specific Heats of GasesEasy2 minQB

PhysicsEasyinteger

A system absorbs 120 kJ of heat and does 80 kJ of work in one process. It is then brought back to its original state by a second process in which it absorbs 90 kJ. Find the work done by the system in the second process in kJ.

Answer:

130

Solution:

First process: $Δ U = 120 - 80 = 40$ kJ. Returning needs $Δ U = - 40$ kJ. Second process: $W = Q - Δ U = 90 + 40 = 130$ kJ.

Subject:PhysicsTopic:Heat & ThermoSubtopic:Thermodynamics Laws & Specific Heats of Gases

⏱ 2mℹ️ Source: QB

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