Two particles P and Q describe SHMs of the same period and amplitude along the same line about the same equilibrium position O . When P and Q are on opposite sides of O at the same distance from it, t

Question

Two particles P and Q describe SHMs of the same period and amplitude along the same line about the same equilibrium position O . When P and Q are on opposite sides of O at the same distance from it, they have the same speed of 1.2 m/s in the same direction. When their displacements are the same they have the same speed of 1.6 m/s in opposite directions. The maximum velocity of either particle is:

TestHub · Accepted Answer

With phase difference ϕ : the first condition gives speed v ma x ​ cos ( ϕ /2 ) = 1.2 ; the second gives v ma x ​ sin ( ϕ /2 ) = 1.6 . So v ma x ​ = 1.44 + 2.56 ​ = 2 m/s.

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