A black body is heated from 2 7 ∘ C to 17 7 ∘ C. Find the factor by which the rate of energy radiation increases (two decimals).

T goes from 300 K to 450 K. The factor is ( 300 450 ) 4 = 1.5 4 = 5.06 .

Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoHeat TransferEasy2 min

PhysicsEasynumerical

A black body is heated from $2 7^{\circ}$ C to $17 7^{\circ}$ C. Find the factor by which the rate of energy radiation increases (two decimals).

Answer:

5.06

Solution:

$T$ goes from 300 K to 450 K. The factor is $(\frac{450}{300})^{4} = 1.5^{4} = 5.06$ .

Subject:PhysicsTopic:Heat & ThermoSubtopic:Heat Transfer

⏱ 2m

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