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PhysicsNLMMedium2 minQB

PhysicsMediummultiple choice

When the system shown here is pulled by force F, the 1 kg block remains stationary relative to the wedge. There is no friction anywhere.

Answer:

A, C

Solution:

$F = 4 a$

$F sin 3 7^{\circ} + N cos 3 7^{\circ} = 10$

$F cos 3 7^{\circ} - N sin 3 7^{\circ} = 1 a$

$3 \times 3 F + 4 N = 50$

$4 \times 4 F - 3 N = a$

$25 F = 150 + 4 a$

$100 a - 4 a = 150$

$a = \frac{150}{96} \Rightarrow F_{8} = \frac{150}{96} \times 4 = 6.25 N$

Stream:JEESubject:PhysicsTopic:NLM

⏱ 2mℹ️ Source: QB

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