A flat lead cylinder floats in mercury at 0 ∘ C . ρ P b = 11.34 g / cm 3 , ρ H g = 13.6 g / cm 3 at 0 ∘ C ; γ H g = 1.8 × 1 0 − 4 ∘ C − 1 , γ P b = 8.7 × 1 0 − 5 ∘ C − 1 . Find the fraction of

Question

A flat lead cylinder floats in mercury at 0 ∘ C . ρ P b ​ = 11.34 g / cm 3 , ρ H g ​ = 13.6 g / cm 3 at 0 ∘ C ; γ H g ​ = 1.8 × 1 0 − 4 ∘ C − 1 , γ P b ​ = 8.7 × 1 0 − 5 ∘ C − 1 . Find the fraction of the lead's volume submerged at 100°C (3 decimals).

TestHub · Accepted Answer

At 0 ∘ C : f = 11.34/13.6 = 0.834 . At 10 0 ∘ C : f ′ = f 1 + y P b ​ Δ T 1 + y H ​ Δ T ​ = 0.834 × 1.0087 1.018 ​ = 0.842 . It floats lower.

Physics - Heat & Thermo Question with Solution | TestHub

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