A horizontal tube 80 cm long is closed at both ends. An 8 cm mercury column sits in the middle with air at 76 cm Hg on each side. By what distance does the mercury move when the tube is held vertical

Question

A horizontal tube 80 cm long is closed at both ends. An 8 cm mercury column sits in the middle with air at 76 cm Hg on each side. By what distance does the mercury move when the tube is held vertical (cm, two decimals)? Each air column is 36 cm.

Answer:

1.89

Solution:

The column moves down $x$ : $\frac{76 \times 36}{36 - x} - \frac{76 \times 36}{36 + x} = 8$ , which gives $x = 1.89$ cm.

TestHub · Accepted Answer

The column moves down x : 36 − x 76 × 36 ​ − 36 + x 76 × 36 ​ = 8 , which gives x = 1.89 cm.

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