Physics - NLM Question with Solution | TestHub

$\mathrm{N}\mathrm{mg}\cos \theta =0$ $\mathrm{mg}\sin \theta =\mathrm{ma}$ $\mathrm{mg}{\sin }^{-2}\theta =\mathrm{ma}\sin \theta$ $\mathrm{mg}-\mathrm{mg}{\cos }^2\theta =\mathrm{ma}\sin \theta$ $\mathrm{mg}-\mathrm{N}\cos \theta =\mathrm{ma}\sin \theta ]$