An object of mass M is dropped from a height H above the ground. The object crashes into some soft earth and comes to rest by compressing the earth a distance of H/2. Assuming that air resistance is n

Question

An object of mass M is dropped from a height H above the ground. The object crashes into some soft earth and comes to rest by compressing the earth a distance of H/2. Assuming that air resistance is negligible, what is the magnitude of the average constant force exerted by the ground on the object while coming to rest?

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Answer:

D

Solution:

$Average acceleration = \frac{v ^{-} - u ^{-}}{25} \Rightarrow \frac{v - ∠ g π}{2 \times u /2} = - 2 g$

$F - my = 2 mg \Rightarrow F = 3 mg$

TestHub · Accepted Answer

Average acceleration = 25 v − − u − ​ ⇒ 2 × u /2 v − ∠ g π ​ = − 2 g ​ F − my = 2 mg ​ ⇒ F = 3 mg ​

Physics - NLM Question with Solution | TestHub

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