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PhysicsSHMOscillations and SHMEasy2 min

PhysicsEasyinteger

A spring of stiffness 300 N/m is cut into two parts of length ratio $1 : 2$ . Find the stiffness of the longer part, in N/m.

Answer:

450

Solution:

The longer part is $\frac{2}{3}$ of the length, so $k = 300 \times \frac{3}{2} = 450$ N/m.

Subject:PhysicsTopic:SHMSubtopic:Oscillations and SHM

⏱ 2m

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