A linear harmonic oscillator of force constant 2 × 1 0 6 N/m and amplitude 0.01 m has a total mechanical energy of 160 J. Its:

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PhysicsSHMOscillations and SHMMedium2 min

PhysicsMediummultiple choice

A linear harmonic oscillator of force constant $2 \times 1 0^{6}$ N/m and amplitude 0.01 m has a total mechanical energy of 160 J. Its:

Options:(select one or more)

Answer:

B, C

Solution:

$\frac{1}{2} k A^{2} = \frac{1}{2} (2 \times 1 0^{6}) (1 0^{- 4}) = 100$ J is the swing of energy. Max K.E. = $100$ J, so min P.E. = $160 - 100 = 60$ J and max P.E. = $160$ J.

Subject:PhysicsTopic:SHMSubtopic:Oscillations and SHM

⏱ 2m

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