The temperature gradient in a rod of length 0.8 m is 6 0 ∘ C/m. The hotter end is at 2 5 ∘ C. Find the temperature in ∘ C of the cooler end.

The difference is 60 × 0.8 = 4 8 ∘ C. The cooler end is at 25 − 48 = − 2 3 ∘ C.

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Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoHeat TransferEasy2 min

PhysicsEasyinteger

The temperature gradient in a rod of length 0.8 m is $6 0^{\circ}$ C/m. The hotter end is at $2 5^{\circ}$ C. Find the temperature in $^{\circ}$ C of the cooler end.

Answer:

-23

Solution:

The difference is $60 \times 0.8 = 4 8^{\circ}$ C. The cooler end is at $25 - 48 = - 2 3^{\circ}$ C.

Subject:PhysicsTopic:Heat & ThermoSubtopic:Heat Transfer

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