The ends of a 50 cm rod are at 9 0 ∘ C and 1 0 ∘ C in the steady state. Find the temperature in ∘ C at 15 cm from the hot end.

The gradient is 50 80 = 1.6 ∘ C c m − 1 . T = 90 − 1.6 × 15 = 6 6 ∘ C.

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Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoHeat TransferMedium2 min

PhysicsMediuminteger

The ends of a 50 cm rod are at $9 0^{\circ}$ C and $1 0^{\circ}$ C in the steady state. Find the temperature in $^{\circ}$ C at 15 cm from the hot end.

Answer:

Solution:

The gradient is $\frac{80}{50} = 1.6^{\circ}$ C $c m^{- 1}$ . $T = 90 - 1.6 \times 15 = 6 6^{\circ}$ C.

Subject:PhysicsTopic:Heat & ThermoSubtopic:Heat Transfer

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