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Physics - Center of Mass Question with Solution | TestHub

PhysicsCenter of MassImpulse momentum theoremMedium2 minQB

PhysicsMediumsingle choice

A particle is acted upon by a force for 1 sec. Whose x component remains constant $F_{x} = 30 N$ but y and z components vary with time as shown. The magnitude of change in momentum (in kg m/s) of particle in 1 sec .

Options:

Answer:

Solution:

Impulse components over 1 s: $J_{x} = 30 \times 1 = 30$ , $J_{y} = \frac{1}{2} \times 40 \times 1 = 20$ , $J_{z} = \frac{1}{2} \times 80 \times 1 = 40$ (areas under the F-t graphs).

$∣Δ p ∣ = 3 0^{2} + 2 0^{2} + 4 0^{2} = 2900 = 1029 kg m/s$

Ans. (D)

Stream:JEESubject:PhysicsTopic:Center of MassSubtopic:Impulse momentum theorem

⏱ 2mℹ️ Source: QB

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