Start Free Mock LoginAlready registered? Login here

Physics - Geometrical Optics Question with Solution | TestHub

PhysicsGeometrical OpticsReflection at curved surfaceMedium3 minQB

PhysicsMediuminteger

A rod of length 5 cm lies along the principal axis of a concave mirror of focal length 10 cm in such a way that the end nearer from the pole is at focus. Find distance (in cm) of the image of farther end from the pole.

Answer:

Solution:

Nearer end at the focus: $u = 10 cm$ ; farther end at $u = 15 cm$ .

$\frac{1}{v} = \frac{1}{10} - \frac{1}{15} = \frac{1}{30} \Rightarrow v = 30 cm$

Answer: 30

Stream:JEESubject:PhysicsTopic:Geometrical OpticsSubtopic:Reflection at curved surface

⏱ 3mℹ️ Source: QB

Doubts & Discussion

Loading discussions...