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Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoThermodynamics Laws & Specific Heats of GasesMedium2 minQB

PhysicsMediuminteger

A gas goes from state 1 to state 2 along path $a$ doing 180 J of work, and along path $b$ doing 120 J of work. Its internal energy rises by 100 J. Find $Q_{a} - Q_{b}$ in joules.

Answer:

Solution:

$Δ U$ is the same for both. $Q_{a} = 100 + 180 = 280$ J and $Q_{b} = 100 + 120 = 220$ J. Difference 60 J.

Subject:PhysicsTopic:Heat & ThermoSubtopic:Thermodynamics Laws & Specific Heats of Gases

⏱ 2mℹ️ Source: QB

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