A black body of area 0.2 m 2 is at 52 7 ∘ C. Find the heat radiated in 2 minutes in kJ (one decimal; σ = 5.67 × 1 0 − 8 ).

P = σ A T 4 = 5.67 × 1 0 − 8 × 0.2 × 80 0 4 = 4645 W. In 120 s: 557.4 kJ.

Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoHeat TransferMedium2 min

PhysicsMediumnumerical

A black body of area 0.2 $m^{2}$ is at $52 7^{\circ}$ C. Find the heat radiated in 2 minutes in kJ (one decimal; $σ = 5.67 \times 1 0^{- 8}$ ).

Answer:

557.40

Solution:

$P = σ A T^{4} = 5.67 \times 1 0^{- 8} \times 0.2 \times 80 0^{4} = 4645$ W. In 120 s: $557.4$ kJ.

Subject:PhysicsTopic:Heat & ThermoSubtopic:Heat Transfer

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