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PhysicsNLMMedium2 minQB

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A spring has length □ and spring constant k . It is cut into two pieces of length $ℓ_{1}$ and $ℓ_{2}$ such that $ℓ_{1} = n ℓ_{2}$ . The force constant of spring of length $ℓ_{1}$ is

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Solution:

$k \propto \frac{1}{ℓ} ∴ \frac{k _{1}}{k} = \frac{ℓ}{ℓ _{1}} = \frac{ℓ _{1} + ℓ _{2}}{ℓ _{1}} = \frac{1 + ℓ _{2}}{ℓ _{1}} = 1 + \frac{1}{n} \Rightarrow k_{1} = k (1 + \frac{1}{n})]$

Stream:JEESubject:PhysicsTopic:NLM

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