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Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoThermodynamicsMedium2 minQB

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The temperature of n moles of an ideal gas is increased from T to 4T through a process for which pressure $p = a T^{- 1}$ where a is a constant. Then, the work done by the gas is (R is universal gas constant):

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Answer:

Solution:

$p V = n RT$ with $p = \frac{a}{T}$ gives $V = \frac{n R T ^{2}}{a}$ , so $d V = \frac{2 n RT}{a} d T$ .

$W = \int_{T}^{4 T} p d V = \int_{T}^{4 T} \frac{a}{T} \cdot \frac{2 n RT}{a} d T = \int_{T}^{4 T} 2 n R d T = 6 n RT$

Stream:JEESubject:PhysicsTopic:Heat & ThermoSubtopic:Thermodynamics

⏱ 2mℹ️ Source: QB

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